checksums and data types

I'm creating a checksum column in a table that is to be calculated over several columns within the table.

One of the columns to be included in the checksum formula has a data type ntext.

But on trying to complete this new table design (or similarly using alter table in QA) - both return an error stating that the data type is invalid for the checksum function.

This happens for both ntext and text data types.

Can anyone tell me if there is a way round this without having to change the data type - or the valid data types that can be used for the checksum funciton?

Also reasons why would be helpful!

Thanksplease ignore - http://www.dbforums.com/t989557.html shows this not to be possible...

nevermind|||you might want to try something like so:

SELECT checksum(col1,col2,CAST(CAST(col3 as varchar(1)) as int))
FROM testTable

I am not sure if this totally works. Text and Ntext are meant to hold large amounts of text data like notes field in a customer service application. There is no implicit data conversion between int and ntext\text in sql server because that is just one of the rules and it would'nt make much since do so. To tell the truth it sounds like your problem is a design issue. However you can explicitly convert data types as shown above but please keep in mind if you try to cast character data in col3 above to an int, you will recieve an error. So you might have to add an IsNumeric in there as well.|||CHECKSUM works with non-numeric data, so there is no need to recast as INT in your formula.

Though I'm still not sure that is going to give him what he needs...|||Why are you doing this? To enforce data integrity upon INSERT/UPDATE? Or to support some business rule? Either way you're already using a database, so the answer should be in design, not checksum-based tricks.|||hey trotsky!!
calm down.|||I'd love to hear the reason behind this... I can't for the life of me figure out why you might want/need to do it. I'm also with rdjabarov, and think that this smells very strongly of a high GQ (geek quotient) workaround for a case of poor relational design!

-PatP|||that's twice that you have agreed with RDjabarov.
hmmmmmmm is the feud over?

:D|||Feud? Did I miss a meeting?

-PatP|||must have been the coma. when i first go here you guys would go at it like turtles and bunnies.

Checking Date column within the same table - DDL included

Hi all,
I have included All sample data, just copy and paste in Query Analizer
I would like to modify the query below to return all that had a prior
"pretest" 30 days prior or equal to
the "test". so the return result that I would like would look like this:
1 A 1997/12/08 pretest
1 A 1997/12/09 test
1 A 1997/12/11 test
3 C 1997/12/18 pretest
3 C 1997/12/19 test
4 D 1997/12/15 pretest
4 D 1997/12/16 test
5 E 1997/12/17 test
5 E 1997/12/17 pretest
6 F 1998/08/03 pretest
6 F 1998/08/04 test
6 F 1998/08/18 test
IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME =
'AppointmentTable')
Begin
DROP TABLE AppointmentTable
End
CREATE TABLE [AppointmentTable] (
[tableid] [int] IDENTITY (1, 1) NOT NULL ,
[nameid] [numeric](18, 0) NOT NULL ,
[fullname] [varchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL ,
[appointmentdate] [datetime] NOT NULL ,
[type] [varchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL
) ON [PRIMARY]
GO
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('1','A', '1997/12/08', 'pretest')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('1','A', '1997/12/09', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('1','A', '1997/12/11', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('1','A', '2003/05/07', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('1','A', '2003/05/08', 'pretest')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('2','B', '1997/12/12', 'pretest')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('2','B', ' 1998/02/24', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('3','C', '1997/12/18', 'pretest')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('3','C', '1997/12/19', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('4','D', '1997/12/15', 'pretest')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('4','D', '1997/12/16', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('5','E', '1997/12/17', 'pretest')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('5','E', '1997/12/17', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('6','F', '1998/08/03', 'pretest')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('6','F', '1998/08/04', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('6','F', '1998/08/18', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('6','F', '1999/07/07', 'pretest')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('6','F', '1999/08/31', 'test')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
VALUES ('6','F', '2001/05/15', 'test')
SELECT nameid as [Name ID],fullname as [Full Name],
CONVERT(varchar,appointmentdate, 111) as [Appointment Date], type as [Test
Type]
FROM AppointmentTable
ORDER BY [Name ID],[Full Name],[Appointment Date],[Test Type]DESC
IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME =
'AppointmentTable')
Begin
DROP TABLE AppointmentTable
End
Thanks for your help
GerryThis works using a UNION!! would there be a better way to write it?
Select u1.nameid as [nameid],u1.fullname as [Full Name], u1.appointmentdate
as [Exam Date], u1.type as [Procedure Type]
from appointmenttable u1
where u1.type = 'pretest'
and exists (SELECT * from appointmenttable u2
where u1.nameid = u2.nameid
and u2.type = 'test'
and u1.appointmentdate <= u2.appointmentdate
and Datediff(day,u1.appointmentdate ,u2.appointmentdate)
<= 30)
UNION
Select u2.nameid as [nameid],u2.fullname as [Full Name], u2.appointmentdate
as [Exam Date], u2.type as [Procedure Type]
from appointmenttable u2
where u2.type = 'test'
and exists (SELECT * from appointmenttable u1
where u1.nameid = u2.nameid
and u1.type = 'pretest'
and u1.appointmentdate <= u2.appointmentdate
and Datediff(day,u1.appointmentdate ,u2.appointmentdate)
<= 30)
ORDER BY [nameid],[Full Name],[Exam Date],[Procedure Type]DESC
thanks
Gerry
"gv" <viatorg@.musc.edu> wrote in message
news:OgIrxTr7FHA.1028@.TK2MSFTNGP11.phx.gbl...
> Hi all,
> I have included All sample data, just copy and paste in Query Analizer
> I would like to modify the query below to return all that had a prior
> "pretest" 30 days prior or equal to
> the "test". so the return result that I would like would look like this:
> 1 A 1997/12/08 pretest
> 1 A 1997/12/09 test
> 1 A 1997/12/11 test
> 3 C 1997/12/18 pretest
> 3 C 1997/12/19 test
> 4 D 1997/12/15 pretest
> 4 D 1997/12/16 test
> 5 E 1997/12/17 test
> 5 E 1997/12/17 pretest
> 6 F 1998/08/03 pretest
> 6 F 1998/08/04 test
> 6 F 1998/08/18 test
>
> IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME =
> 'AppointmentTable')
> Begin
> DROP TABLE AppointmentTable
> End
> CREATE TABLE [AppointmentTable] (
> [tableid] [int] IDENTITY (1, 1) NOT NULL ,
> [nameid] [numeric](18, 0) NOT NULL ,
> [fullname] [varchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL ,
> [appointmentdate] [datetime] NOT NULL ,
> [type] [varchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL
> ) ON [PRIMARY]
> GO
>
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('1','A', '1997/12/08', 'pretest')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('1','A', '1997/12/09', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('1','A', '1997/12/11', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('1','A', '2003/05/07', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('1','A', '2003/05/08', 'pretest')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('2','B', '1997/12/12', 'pretest')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('2','B', ' 1998/02/24', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('3','C', '1997/12/18', 'pretest')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('3','C', '1997/12/19', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('4','D', '1997/12/15', 'pretest')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('4','D', '1997/12/16', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('5','E', '1997/12/17', 'pretest')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('5','E', '1997/12/17', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('6','F', '1998/08/03', 'pretest')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('6','F', '1998/08/04', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('6','F', '1998/08/18', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('6','F', '1999/07/07', 'pretest')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('6','F', '1999/08/31', 'test')
> INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type)
> VALUES ('6','F', '2001/05/15', 'test')
>
> SELECT nameid as [Name ID],fullname as [Full Name],
> CONVERT(varchar,appointmentdate, 111) as [Appointment Date], type as [Test
> Type]
> FROM AppointmentTable
> ORDER BY [Name ID],[Full Name],[Appointment Date],[Test Type]DESC
>
> IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME =
> 'AppointmentTable')
> Begin
> DROP TABLE AppointmentTable
> End
> Thanks for your help
> Gerry
>
>
>
>
>
>
>
>
>
>
>|||See if this helps:
select aouter.*
from #AppointmentTable aouter
where exists
(select * from #AppointmentTable
where aouter.nameid = nameid
and ((aouter.type = 'test'
and type = 'pretest'
and DateDiff(d,appointmentdate,aouter.appointmentdate) between 0 and 30)
or (aouter.type = 'pretest'
and type = 'test'
and DateDiff(d,aouter.appointmentdate,appointmentdate) between 0 and 30))
)
"gv" wrote:

> This works using a UNION!! would there be a better way to write it?
> Select u1.nameid as [nameid],u1.fullname as [Full Name], u1.appointmentdate
> as [Exam Date], u1.type as [Procedure Type]
> from appointmenttable u1
> where u1.type = 'pretest'
> and exists (SELECT * from appointmenttable u2
> where u1.nameid = u2.nameid
> and u2.type = 'test'
> and u1.appointmentdate <= u2.appointmentdate
> and Datediff(day,u1.appointmentdate ,u2.appointmentdat
e)
> <= 30)
> UNION
> Select u2.nameid as [nameid],u2.fullname as [Full Name], u2.appointmentdate
> as [Exam Date], u2.type as [Procedure Type]
> from appointmenttable u2
> where u2.type = 'test'
> and exists (SELECT * from appointmenttable u1
> where u1.nameid = u2.nameid
> and u1.type = 'pretest'
> and u1.appointmentdate <= u2.appointmentdate
> and Datediff(day,u1.appointmentdate ,u2.appointmentdat
e)
> <= 30)
> ORDER BY [nameid],[Full Name],[Exam Date],[Procedure Type]DESC
> thanks
> Gerry
>
>
> "gv" <viatorg@.musc.edu> wrote in message
> news:OgIrxTr7FHA.1028@.TK2MSFTNGP11.phx.gbl...
>
>|||THANKS!!! BIG HELP!!!!
Gerry
"Absar Ahmad" <AbsarAhmad@.discussions.microsoft.com> wrote in message
news:0EF60332-ADE8-4C4D-9481-A1E8FB733234@.microsoft.com...
> See if this helps:
> select aouter.*
> from #AppointmentTable aouter
> where exists
> (select * from #AppointmentTable
> where aouter.nameid = nameid
> and ((aouter.type = 'test'
> and type = 'pretest'
> and DateDiff(d,appointmentdate,aouter.appointmentdate) between 0 and 30)
> or (aouter.type = 'pretest'
> and type = 'test'
> and DateDiff(d,aouter.appointmentdate,appointmentdate) between 0 and 30))
> )
> "gv" wrote:
>|||thanks again for your help
What if I wanted to only return the latest 65 distinct nameid based on
appointmentdate?
thanks
Gerry
"Absar Ahmad" <AbsarAhmad@.discussions.microsoft.com> wrote in message
news:0EF60332-ADE8-4C4D-9481-A1E8FB733234@.microsoft.com...
> See if this helps:
> select aouter.*
> from #AppointmentTable aouter
> where exists
> (select * from #AppointmentTable
> where aouter.nameid = nameid
> and ((aouter.type = 'test'
> and type = 'pretest'
> and DateDiff(d,appointmentdate,aouter.appointmentdate) between 0 and 30)
> or (aouter.type = 'pretest'
> and type = 'test'
> and DateDiff(d,aouter.appointmentdate,appointmentdate) between 0 and 30))
> )
> "gv" wrote:
>|||Hopefully this will help u:
select top 65 a.nameid
from #AppointmentTable a
where exists
(select * from #AppointmentTable b
where a.nameid = b.nameid and a.type <> b.type
and
((a.type = 'pretest' and datediff(d,a.appointmentdate,b.appointmentdate)
between 0 and 30)
or
(a.type = 'test' and datediff(d,b.appointmentdate,a.appointmentdate) between
0 and 30))
)
group by a.nameid
order by max(a.appointmentdate) desc
"gv" wrote:

> thanks again for your help
> What if I wanted to only return the latest 65 distinct nameid based on
> appointmentdate?
> thanks
> Gerry|||Thank you so much for your help!!!
Very Close!
The 65 needs to be Distinct from column namid so there could actually be
over 130 rows returned but only 65 different
nameid and within each nameid the pretest needs to be listed first. But
within each different nameid
you have it right where the order of Max appointmentdate is coming first.
Thanks again for your help Absar
Gerry :< )
"Absar Ahmad" <AbsarAhmad@.discussions.microsoft.com> wrote in message
news:74B787F2-88D4-4120-858B-1F1B8FA8B34A@.microsoft.com...
> Hopefully this will help u:
> select top 65 a.nameid
> from #AppointmentTable a
> where exists
> (select * from #AppointmentTable b
> where a.nameid = b.nameid and a.type <> b.type
> and
> ((a.type = 'pretest' and datediff(d,a.appointmentdate,b.appointmentdate)
> between 0 and 30)
> or
> (a.type = 'test' and datediff(d,b.appointmentdate,a.appointmentdate)
> between
> 0 and 30))
> )
> group by a.nameid
> order by max(a.appointmentdate) desc
> "gv" wrote:
>
>|||On Wed, 23 Nov 2005 14:29:56 -0500, gv wrote:

>Thank you so much for your help!!!
>Very Close!
>The 65 needs to be Distinct from column namid so there could actually be
>over 130 rows returned but only 65 different
>nameid and within each nameid the pretest needs to be listed first. But
>within each different nameid
>you have it right where the order of Max appointmentdate is coming first.
>Thanks again for your help Absar
>Gerry :< )
Hi Gerry,
Maybe this is what you need?
(Note - I also changed the way to determine the date range in order to
have a better chance of using an index -if there is any- on the
appointmentdate column).
SELECT nameid as [Name ID],fullname as [Full Name],
CONVERT(varchar,appointmentdate, 111) as [Appointment
Date],
type as [Test Type]
FROM AppointmentTable AS a
WHERE EXISTS
(SELECT *
FROM AppointmentTable AS b
WHERE b.nameid = a.nameid
AND b.type <> a.type
AND b.appointmentdate BETWEEN CASE WHEN a.type = 'test'
THEN DATEADD (day, -30,
a.appointmentdate)
ELSE a.appointmentdate
END
AND CASE WHEN a.type = 'test'
THEN a.appointmentdate
ELSE DATEADD (day, 30,
a.appointmentdate)
END)
AND a.nameid IN
(SELECT TOP 65 c.nameid
FROM AppointmentTable AS c
WHERE EXISTS
(SELECT *
FROM AppointmentTable AS d
WHERE d.nameid = c.nameid
AND d.type <> c.type
AND d.appointmentdate BETWEEN CASE WHEN c.type = 'test'
THEN DATEADD (day, -30,
c.appointmentdate)
ELSE c.appointmentdate
END
AND CASE WHEN c.type = 'test'
THEN c.appointmentdate
ELSE DATEADD (day, 30,
c.appointmentdate)
END)
GROUP BY c.nameid
ORDER BY MAX(appointmentdate))
ORDER BY [Name ID],[Full Name],[Appointment Date],[Test Type] DESC
I've tested this against the test data you supplied (thanks for that, by
the way!). If I change the TOP 65 to TOP 3, I only get the results for
nameid 1, 4, and 5.
Best, Hugo
--
(Remove _NO_ and _SPAM_ to get my e-mail address)|||Thanks so much for your help!
Almost got it.
I've added some more test data and included your query. Doesn't return the c
orrect top 6 based on appointmentdate. And
within each id the appointmentdate should be ordered by earlist date first b
ut it is correct to order the latest date of the id first.
sorry if I was not clear enough before. I would also like it to only return
those that had "checked"
at least once next to "test" within a group. See all sample data below tha
nks again Gerry
Returns this:
7 G 2005/07/07 test checked
7 G 2005/07/06 pretest -
8 H 2005/06/24 test checked
8 H 2005/06/22 test checked
8 H 2005/06/19 pretest -
9 I 2005/05/22 test
9 I 2005/05/20 pretest -
10 J 2005/04/10 test checked
10 J 2005/04/05 pretest -
11 K 2005/03/16 test checked
11 K 2005/03/14 pretest -
7 G 2004/05/05 test
7 G 2004/05/04 pretest -
7 G 2002/09/25 test
7 G 2002/09/04 pretest -
6 F 1998/08/18 test
6 F 1998/08/04 test checked
6 F 1998/08/03 pretest -
7 G 1992/07/30 test
7 G 1992/07/08 pretest -
should return this and in this order:
7 G 2005/07/06 pretest -
7 G 2005/07/07 test checked
8 H 2005/06/19 pretest -
8 H 2005/06/22 test checked
8 H 2005/06/24 test
9 I 2005/05/20 pretest -
9 I 2005/05/22 test checked
10 J 2005/04/05 pretest -
10 J 2005/04/10 test checked
11 K 2005/03/14 pretest -
11 K 2005/03/16 test checked
7 G 2004/05/04 pretest -
7 G 2004/05/05 test
IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = 'Appo
intmentTable')
Begin
DROP TABLE AppointmentTable
End
CREATE TABLE [AppointmentTable] (
[tableid] [int] IDENTITY (1, 1) NOT NULL ,
[nameid] [numeric](18, 0) NOT NULL ,
[fullname] [varchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL ,
[appointmentdate] [datetime] NOT NULL ,
[type] [varchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[status] [varchar] (15) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL
) ON [PRIMARY]
GO
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('1','A', '1997/12/08', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('1','A', '1997/12/09', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('1','A', '1997/12/11', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('1','A', '2003/05/07', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('1','A', '2003/05/08', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('2','B', '1997/12/12', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('2','B', ' 1998/02/24', 'test','')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('3','C', '1997/12/18', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('3','C', '1997/12/19', 'test','')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('4','D', '1997/12/15', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('4','D', '1997/12/16', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('5','E', '1997/12/17', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('5','E', '1997/12/17', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('6','F', '1998/08/03', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('6','F', '1998/08/04', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('6','F', '1998/08/18', 'test','')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('6','F', '1999/07/07', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('6','F', '1999/08/31', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('6','F', '2001/05/15', 'test','')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('7','G', '2005/07/06', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('7','G', '2005/07/07', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('7','G', '2004/05/04', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('7','G', '2004/05/05', 'test','')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('7','G', '2002/09/04', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('7','G', '2002/09/25', 'test','')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('7','G', '1992/07/08', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('7','G', '1992/07/30', 'test','')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('8','H', '2005/06/19', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('8','H', '2005/06/22', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('8','H', '2005/06/24', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('9','I', '2005/05/20', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('9','I', '2005/05/22', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('10','J', '2005/04/05', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('10','J', '2005/04/10', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('11','K', '2005/03/14', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('11','K', '2005/03/16', 'test','checked')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('12','L', '2005/02/08', 'pretest','-')
INSERT INTO AppointmentTable (nameid,fullname,appointmentdate,type,st
atus)
VALUES ('12','L', '2005/03/11', 'test','checked')
SELECT nameid as [Name ID],fullname as [Full Name],
CONVERT(varchar,appointmentdate, 111) as [Appointment Date],
type as [Test Type],status
FROM AppointmentTable AS a
WHERE EXISTS
(SELECT *
FROM AppointmentTable AS b
WHERE b.nameid = a.nameid
AND b.type <> a.type
AND b.appointmentdate BETWEEN CASE WHEN a.type = 'test'
THEN DATEADD (day, -30,a.appointmentdate)
ELSE a.appointmentdate
END
AND CASE WHEN a.type = 'test'
THEN a.appointmentdate
ELSE DATEADD (day, 30,a.appointmentdate)
END)
AND a.nameid IN
(SELECT TOP 6 c.nameid
FROM AppointmentTable AS c
WHERE EXISTS
(SELECT *
FROM AppointmentTable AS d
WHERE d.nameid = c.nameid
AND d.type <> c.type
AND d.appointmentdate BETWEEN CASE WHEN c.type = 'test'
THEN DATEADD (day, -30,c.appointmentdate)
ELSE c.appointmentdate
END
AND CASE WHEN c.type = 'test'
THEN c.appointmentdate
ELSE DATEADD (day, 30,c.appointmentdate)
END)
GROUP BY c.nameid
ORDER BY MAX(appointmentdate)DESC )
ORDER BY [Appointment Date]desc
IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = 'Appo
intmentTable')
Begin
DROP TABLE AppointmentTable
End|||On Mon, 28 Nov 2005 15:06:38 -0500, gv wrote:

>Thanks so much for your help!
>Almost got it.
>I've added some more test data and included your query. Doesn't return the
correct top 6 based on appointmentdate. And
>within each id the appointmentdate should be ordered by earlist date first
but it is correct to order the latest date of the id first.
>sorry if I was not clear enough before. I would also like it to only return
those that had "checked"
>at least once next to "test" within a group. See all sample data below thanks
again Gerry
Hi Gerry,
Thanks for posting CREATE TABLE and INSERT statements. Helps a lot!
Before I start writing a query, let me clarify what I think you want to
get from your data. Correct me if I'm wrong.
- You need to find "pretest" with a "test" for the same nameid in the
next 30 days.
- Of those, you only wwant to select the 6 (or 65) most recent rows.
- The "pretest" rows should be returned in the order of most recent row
first.
- But the "test" rows should FOLLOW the accompanying "pretest" row, and
should be presented oldest first.
Finally, in the required output you have given, you have changed the
contents of these rows:

>8 H 2005/06/24 test checked
>8 H 2005/06/22 test checked
to this:

>8 H 2005/06/22 test checked
>8 H 2005/06/24 test
Why did you omit "checked" on this row? Why didn't you omit it on any
other rows? I don't understand that part of your requirement.
Best, Hugo
--
(Remove _NO_ and _SPAM_ to get my e-mail address)